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=72V-4V^2
We move all terms to the left:
-(72V-4V^2)=0
We get rid of parentheses
4V^2-72V=0
a = 4; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·4·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*4}=\frac{0}{8} =0 $$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*4}=\frac{144}{8} =18 $
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